Hvorfor er volumet av en kule det det er?

[danilovic]

...Nemlig V=(4×pi׳)/3?

 

Til opplysning er pi tilnærmet lik 3,1415926535897932384626433832795028841971693993751058209749445923078164062862089986280348253421170679821480865132823.

[sybbelybb]

bare at pi har ganske mange flere siffer bak komma, stemmer ikke det?

[danilovic]

bare at pi har ganske mange flere siffer bak komma, stemmer ikke det?

Et bar billioner ja.

[sybbelybb]

3.141592653589793238462643383279502884197169399375105820974944

5923078164062862089986280348253421170679821480865132823066470

9384460955058223172535940812848111745028410270193852110555964

4622948954930381964428810975665933446128475648233786783165271

2019091456485669234603486104543266482133936072602491412737245

8700660631558817488152092096282925409171536436789259036001133

0530548820466521384146951941511609433057270365759591953092186

1173819326117931051185480744623799627495673518857527248912279

3818301194912983367336244065664308602139494639522473719070217

9860943702770539217176293176752384674818467669405132000568127

1452635608277857713427577896091736371787214684409012249534301

4654958537105079227968925892354201995611212902196086403441815

9813629774771309960518707211349999998372978049951059731732816

0963185950244594553469083026425223082533446850352619311881710

1000313783875288658753320838142061717766914730359825349042875

5468731159562863882353787593751957718577805321712268066130019

278766111959092164201989...

 

--------------

 

ihvertfall litt mer nøyaktig... men som det sies:

 

Bear in mind that 39 decimal places of is enough to compute the circumference of a circle around the known universe  

to within an accuracy of the radius of a hydrogen atom.

 

hmmm

[John Abrahamsen]

Du ganger opp for 4 sider, så fjerner du 3 sider, siden 1 side er det samme som stumpene som er igjen av prismet....