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Får 500 Intern Serverfeil, hvorfor?

HoaXed

Av HoaXed
i Programmering og webutvikling

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HoaXed

HoaXed

Skrevet
Skrevet

Hællæ,

 

Prøver meg på database prog. med følgende kode; (ja, rotete men øver)

 

Klikk for å se/fjerne innholdet nedenfor
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<html xmlns="http://www.w3.org/1999/xhtml">

<head>

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />

<title>Untitled Document</title>

<link href="../css/style.css" rel="stylesheet" type="text/css" />

<style type="text/css">

<!--

.style3 {font-size: 9px}

-->

</style>

</head>

 

<body>

<?

 

if(isset($ok)) {

 

$database="hoaxedbase";

$host="hoaxedbase.mysql.domeneshop.no";

$username="hoaxedbase";

$password="***";

 

mysql_connect($host, $username, $password) or die (mysql_error());

mysql_select_db($database) or die( "Unable to select database");

 

$result = mysql_query("SELECT * FROM frfr");

 

mysql_fetch_array($result))

 

mysql_query("INSERT INTO frfr (dato, datotil, tekst)

VALUES ('$vdato', '$vdatotil', '$vtekst')");

 

mysql_close($database); }

 

 

?>

<?

 

if(isset($okendre)) {

 

$database="hoaxedbase";

$host="hoaxedbase.mysql.domeneshop.no";

$username="hoaxedbase";

$password="***";

 

mysql_connect($host, $username, $password) or die (mysql_error());

mysql_select_db($database) or die( "Unable to select database");

 

 

mysql_query("UPDATE frfr (dato, datotil, tekst)

VALUES ('$vdato', '$vdatotil', '$vtekst')");

 

mysql_close($database); }

 

 

?>

<label> <form name="ok" method="post">

<label>

ENDRE!

<input name="id" type="text" id="id" value=" <?

$idverdi = $_GET['id'];

 

 

 

echo "$idverdi";

 

 

?>" size="3" readonly="readonly">

</label>

<input name="vdato" type="text" id="vdato" value="<?

$idverdi = $_GET['id'];

 

if(!empty($idverdi)) {

 

$database="hoaxedbase";

$host="hoaxedbase.mysql.domeneshop.no";

$username="hoaxedbase";

$password="***";

 

mysql_connect($host, $username, $password) or die (mysql_error());

mysql_select_db($database) or die( "Unable to select database");

 

$result = mysql_query("SELECT * FROM frfr WHERE id = '$idverdi'");

 

$row = mysql_fetch_array($result))

 

echo "$row['dato']";

 

 

 

mysql_close($database); }

 

 

?>">

</label>

<label>

<input name="vtekst" type="text" id="vtekst" value="<?

$idverdi = $_GET['id'];

if(!empty($idverdi)) {

 

$database="hoaxedbase";

$host="hoaxedbase.mysql.domeneshop.no";

$username="hoaxedbase";

$password="***";

 

mysql_connect($host, $username, $password) or die (mysql_error());

mysql_select_db($database) or die( "Unable to select database");

 

$result = mysql_query("SELECT * FROM frfr WHERE id = '$idverdi'");

 

$row = mysql_fetch_array($result))

 

echo "$row['tekst']";

 

 

 

mysql_close($database); }

 

 

?>">

</label>

<label>

<input name="vdatotil" type="text" id="vdatotil" value="<?php echo date('dmy'); ?>">

</label>

 

<label>

<input type="submit" name="okendre" id="ok" value="Endre">

</label>

</form><form name="ok" method="post">

<label>

LEGGE TIL!

<input name="id" type="text" id="id" readonly="readonly" size="3">

</label>

<input name="vdato" type="text" id="vdato" onClick="this.value='';" value="Dato for arr.">

</label>

<label>

<input name="vtekst" type="text" id="vtekst" onClick="this.value='';" value="Tekst til arr.">

</label>

<label>

<input name="vdatotil" type="text" id="vdatotil" value="<?php echo date('dmy'); ?>">

</label>

 

<label>

<input type="submit" name="ok" id="ok" value="Legg til">

</label>

</form>

<label> </label>

<p>(ikke endre siste!)</p>

<hr>

<p> <?

 

$database="hoaxedbase";

$host="hoaxedbase.mysql.domeneshop.no";

$username="hoaxedbase";

$password="***";

 

mysql_connect($host, $username, $password) or die (mysql_error());

mysql_select_db($database) or die( "Unable to select database");

 

$result = mysql_query("SELECT * FROM frfr");

 

while($row = mysql_fetch_array($result))

{

echo "<td width=\"13%\" valign=\"top\" class=\"tekstinnhold\">$row['dato'] - </td>

<td width=\"87%\" valign=\"top\" class=\"tekstinnhold\">$row['tekst']</td> <a href=\"leggtilviktigedatoer.php?id=$row['id']\">ENDRE!</a>";

echo "<br />";

}

 

mysql_close($database);

 

 

?>  </p>

 

</body>

</html>

 

 

 

Problemet er at når jeg laster opp får jeg 500 intern server feil! Hvorfor? Allt annet fungerer på serveren. Noen som aner? Takk

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Videoannonse

Videoannonse
Annonse
kakkle

kakkle

Skrevet
Skrevet

Prøv å deaktiver "friendly HTTP error messages" i IE, hvis det er det du bruker.

 

Tools -> Internet Options -> Advanced -> Fjern haken ved "show friendly HTTP error messages":

 

post-48508-1191865071_thumb.jpg

 

Kan være du får litt mer "vettug" feilmelding da.

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